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Kx(x-2)+6 find the value of k

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Kx(x-2)+6 find the value of k

Posted by Anil Kumar 6 years, 5 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 5 months ago

We have, kx(x - 2) + 6 = 0
{tex}\Rightarrow k x^{2}-2 k x+6=0{/tex}........(1)
We know that quadratic equation {tex}ax^2+bx+c=0{/tex},a≠0, has equal roots if its discriminant D is 0.

D = 0
{tex}\Rightarrow{/tex}{tex}b^2-4ac=0{/tex}

{tex}\Rightarrow{/tex}4k² - 4(k)6 = 0 [from given quad. equ.(1); a=k≠0, b= -2k, c= 6]
{tex}\Rightarrow{/tex}4k² - 24k = 0
{tex}\Rightarrow{/tex}4k(k - 6) = 0
{tex}\Rightarrow{/tex}k - 6 = 0 [ since, k≠0]
{tex}\Rightarrow{/tex}k = 6
Hence the value of K is 6.

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