The side of a square is …
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Sia ? 6 years, 6 months ago
Side of square = 10cm
For incircle
diameter of circle = side of square
{tex}\Rightarrow r = \frac{{10}}{2} = 5cm{/tex}
{tex} \therefore {/tex} Area of incircle {tex}= \pi {r^2}{/tex}
{tex}= 3.14 \times 5 \times 5{/tex}
78.50 cm2
For circumcircle
AC will be the diameter because {tex} \angle B = 90^\circ {/tex}
Now, In {tex} \triangle ABC{/tex}, by pythagoras theorem
AC2 = AB2 + BC2
{tex}\Rightarrow {/tex} AC2 = 102 + 102
{tex}\Rightarrow {/tex} AC2 = 200
{tex}\Rightarrow AC = \sqrt {200} = 10\sqrt 2 cm{/tex}
{tex} \therefore {/tex} Area of circumcircle {tex}= \pi {r^2}{/tex}
{tex}= 3.14 \times {\left( {5\sqrt 2 } \right)^2}{/tex}
{tex}= 3.14 \times 50{/tex}
= 157cm2
0Thank You