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In a trapezium ABCD,AB||CD and DC=2AB …

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In a trapezium ABCD,AB||CD and DC=2AB ,where E and F lie on BC and AD respectively such that BE / EC = 4/3 . diagonal DB intersect EF at G . prove that 7EF = 11 AB

Posted by Ranjan Kumar 5 years, 8 months ago

CBSE > Class 10 > Mathematics

1 answers

Teerth Raj Singhal 6 years, 10 months ago

BE/EC=4/3, CD=2 AB BE/EC=AF/FD=4/3 ?BGE SIMILAR ?BDC EG/CD= BE/BC EG= 4/7CD SIMILARLY, FG= 3/7 AB ADD I AND II EF=11/7AB

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