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One year ago, a man was …

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One year ago, a man was 8 times as old as his son. Now, his age is equal to the square of his son, s age in year. Find their present ages

    • Posted by Vishal Vishu K. Mathur 6 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Gaurav Seth 6 years, 10 months ago

    Let age of son one yr ago be x 
    age of man one yr ago be 8x
    .....
    age of son after one year = x+1
    age of man after one year = 8x+1
    ....
    now accordind to question..
    8x+1= (x+1)^2
    8x+1=x^2 + 1 +2x
    after solving 
    8x = x^2 +2x
    now...x^2 - 6x=0
    solving this we get ...x=0 and x = 6 but 
    age cant be zero...so..x=6...
    age of son is x+1 = 7 years
    and age of man be 8x+1= 49

    2Thank You

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