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The sum of first three terms of A.P. is 21 and their products is 231. Find the numbers

Posted by Nikhil Kumar 6 years, 10 months ago

CBSE > Class 10 > Mathematics

4 answers

Ram Kushwah 6 years, 10 months ago

Let the No. a-d,a and a+d

Sum: a-d+a+a+d=21

3a=21, a=7

product: a(a-d)(a+d)=231

a(a2-d2)=231

7(49-d2)=231

49-d2=33

d²=16, d={tex}\pm{/tex}4

So numbers are:

3,7,11 or 11,7,3

1Thank You

Yogita Ingle 6 years, 10 months ago

Let the AP is (a-d), a, (a+d)
(a-d)+a+(a+d) =21
3a=21
a=7
(a-d)×a×(a+d)=231
(a×a-d×d) ×a=231
(7×7-d×d)×7=231
(7×7-d×d)=231÷7
(7×7-d×d)=33
d×d=49-33
d×d=16
d=4
Hence, the A. P. is 3, 7, 11.

0Thank You

Puja Sahoo? 6 years, 10 months ago

the A. P. is 3, 7, 11.

2Thank You

Muhammed Shahabas 6 years, 10 months ago

A=3 and d=4...therfore AP is 3,7,11....... And three numbers are 3,7 and 11

1Thank You

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CBSE > Class 10 > Mathematics