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If one zero of the polynomial (a square +9) x square +13x +6a is reciprocal of the other , find the value of a

Posted by Subham Sarma 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Ram Kushwah 6 years, 10 months ago

{tex}\begin{array}{l}(a^2+9)x^2+13x+6a\\\end{array}{/tex}

Supose the zeros are m and 1/m

then

m x 1/m=6a/(a2+9)

a2+9=6a

a2-6a+9=0

(a-3)^2=0

a=3,3

0Thank You

Honey ??? 6 years, 10 months ago

6Thank You

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