Find the sum of n terms …

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Ram Kushwah 6 years, 10 months ago
(4-1/n)+(4-2/n)+.......
=4n-1/n(1+2+3........n)
{tex}\begin{array}{l}\text{=4n-}\frac1{\mathrm n}\times\frac{\mathrm n(\mathrm n+1)}2\\\text{=4n-}\frac{n+1}2\\\text{=}\frac{8n-n-1}2\\\text{=}\frac{7n-1}2\end{array}{/tex}
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