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Find the sum of n terms …

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Find the sum of n terms of the series (4-1/n)+(4-2/n)+....
  • 2 answers

Ram Kushwah 6 years, 10 months ago

(4-1/n)+(4-2/n)+.......

=4n-1/n(1+2+3........n)

{tex}\begin{array}{l}\text{=4n-}\frac1{\mathrm n}\times\frac{\mathrm n(\mathrm n+1)}2\\\text{=4n-}\frac{n+1}2\\\text{=}\frac{8n-n-1}2\\\text{=}\frac{7n-1}2\end{array}{/tex}

Ritika Bisht 6 years, 10 months ago

Sn = (7n-1)/2
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