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Find the point on x-axis which …

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Find the point on x-axis which is equidistant from (2,5) & (-2,9)
  • 2 answers

Ram Kushwah 6 years, 10 months ago

on x axis y= 0

let the coordinates are O (x,0),A(2,5),B=(-2,9)

{tex}\begin{array}{l}\mathrm{OA}=\mathrm{OB}\\\mathrm{OA}^2=\mathrm{OB}^2\\(\mathrm x-2)^2+(0-5)^2=(\mathrm x+2)^2+(0-9)^2\\\mathrm x^2-4\mathrm x+4+25=\mathrm x^2+4\mathrm x+4+81\\-8\mathrm x=81-25=56\\\mathrm x=-7\\\mathrm{hence}\;\mathrm{the}\;\mathrm{point}\;\mathrm O\;(-7,0)\end{array}{/tex}

Puja Sahoo? 6 years, 10 months ago

Check exercise 7.1 of ncert same aisa question hai ncert me... apko proper solution isi app me mil jayega
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