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If n is equals to 2 …

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If n is equals to 2 raise to power 3 into 3 raise to the power 4 into 5 raise to the power 4 into 7 then find the number of consecutive zeros in and where n is a natural number

    • Posted by Vaishnavi Barde 6 years, 6 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Sia ? 6 years, 6 months ago

    Here, prime factorization of N = 2³×54 ×81×7

     =23×54× 81 x 7 

    =23×54×81 x 7

    = (10)3×5 x 81 x 7

    So, number of consecutive zeroes in 23×53 that is in (10)3  is equal to 3

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