Find the sum of all multiples …

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Posted by Sara Sharma 6 years, 10 months ago
- 3 answers
Yogita Ingle 6 years, 10 months ago
504 , 511 , 518 , ....,889, 896 are multiples of 7 between 500 and 900 and these are in Arithmetic progression .
First term = a = 504 , Common difference = a2 - a1 = d = 511 - 504 = 7
Let the number of terms = n
Last term ( L ) = 896
We know that ,
a + ( n - 1 )d = L
504 + ( n - 1 ) 7 = 896
Divide each term with 7 , we get
72 + n - 1 = 128
71 + n = 128
n = 128 - 71
n = 57
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