a²(b+c)+b²(c+a)+c²(a+b)-2b²c

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Yogita Ingle 6 years, 10 months ago
a2(b+ c) + b2(c + a) + c2 (a+ b) - 2b2c
= a2b + a2c + b2c + b2a + c2a + c2b - 2b2c
= a2b + a2c + b2c - 2b2c + b2a + c2a + c2b
= a2b + a2c - b2c + b2a + c2a + c2b
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