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(a-b) x²+(b-c) x+(c-a), it's roots are …

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(a-b) x²+(b-c) x+(c-a), it's roots are equal, then prove that 2a=b+c

    • Posted by Ashwani Singh 6 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Aakash Kaushik 6 years, 10 months ago

    We know that, If the quadratic equation ax²+bx+c=0 whose roots are equal then it's deteminant is equal to zero. (a-b)x²+(b-c)x+(c-a)=0 Deteminant =0 (b-c)² -4(a-b)(c-a)==0 b²+c²-2bc-4ac+4a²+4bc-4ab=0 b²+c²+4a²+4bc-4ac-4ab=0 b²+c²+(-2a)²+2bc+2c(-2a)+2(-2a)b=0 (b+c-2a)²=0 b+c-2a=0 Therefore, b+c=2a Hence proved. I hope this helps you.

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    Posted by Kanika . 1 month, 1 week ago

    CBSE > Class 10 > Mathematics
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