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Posted by Aashka Shah 8 years, 8 months ago
- 2 answers
Payal Singh 8 years, 8 months ago
Electronic Configuration of
Fe = {tex}1s^2 2s^2 2p^6 3s^2 3p^6 3d^6 4s^2{/tex}
Electronic Configuration of
Fe2+ = {tex}1s^2 2s^2 2p^6 3s^2 3p^6 3d^6 {/tex}
Electronic Configuration of
Fe3+ = {tex}1s^2 2s^2 2p^6 3s^2 3p^6 3d^5{/tex}
So Fe3+ has more unpaired electron.
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Aashka Shah 8 years, 8 months ago
But if we look like Fe2+ as Cr and
Fe3+ as V
in that sense then Fe2+ should be the correct,,,,
is my method correct?????
0Thank You