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Using Euclid's division lemma to show …

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Using Euclid's division lemma to show that the cube of any positive integer is of the form 9m,9m+1 or 9m+2 where m is some integer
  • 2 answers

Yogita Ingle 6 years, 10 months ago

Let a be any positive integer and b = 3
a = 3q + r, where q ≥ 0 and 0 ≤ r < 3
 Therefore, every number can be represented as these three forms. There are three cases.
Case 1: When a = 3q,
Where m is an integer such that m =  (3q)3 = 27q3
9(3q3) = 9m
Case 2: When a = 3q + 1,
a3 = (3q +1) 3
a3 = 27q3 + 27q2 + 9q + 1
a3 = 9(3q3 + 3q2 + q) + 1
a3 = 9m + 1
Where m is an integer such that m = (3q3 + 3q2+ q)

Case 3: When a = 3q + 2,
a3 = (3q +2)3
a3 = 27q3 + 54q2 + 36q + 8
a3 = 9(3q3 + 6q2 + 4q) + 8
a3 = 9m + 8
Where m is an integer such that m = (3q3 + 6q2+ 4q)
Therefore, the cube of any positive integer is of the form 9m, 9m + 1, or 9m + 8.

 

Harsha Asiwal 6 years, 10 months ago

Shayad question tha 9m,9m+1or 9m+8
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