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If cos 47' = a ; then find the values of sin43' and tan 43' in terms of a

Posted by Kunal Kumar Tiwari 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 10 months ago

sin43=sin(90-47)=cos47=a

{tex}\begin{array}{l}cot43=\sqrt{1+}\cos ec^243\\=\sqrt{1+\frac1{a^2}}=\frac1a\sqrt{1+a^2}\\\tan43=\frac1{cot43}=\frac a{\sqrt{1+a2}}\end{array}{/tex}

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