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From an extrenal point P two …

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From an extrenal point P two tangent are drawn to the circle with centre O. Prove that OP is the perpendicular bisector of AB.
  • 2 answers

Kitzz Perey 6 years, 10 months ago

And thankx for such question

Kitzz Perey 6 years, 10 months ago

To prove OP os perpendicular bisector of AB in triangle PAC and PBC PA=PB (length of tangent drawn from an xterior point is equal) <PAC=<PBC (through equal sides ) CP=CP through SAS congruence AC=BC cpct Triangle ACP=BCP <ACP=<BCP <ACP+<BCP=18O°(linear pair) 2<ACP=180° <ACP=90°=<BCP
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