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Tan4A+tan2A=sec4A-sec2A

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Tan4A+tan2A=sec4A-sec2A

    • Posted by Samrat Kkkkk 6 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Gaurav Seth 6 years, 10 months ago

    Explanation: Use one of the Pythagorean identity namely,

    sec2A=1+tan2A

     sec4A−sec2A
    =(sec2A)2−sec2A
    =(1+tan2A)2−(1+tan2A)
    =1+2tan2A+tan4A−1−tan2A

    =tan4A+tan2A

    2Thank You

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