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Two pipes running together can fill a cistern in 40/13 minutes. If one pipe takes 3 minutes more than the other to fill it find the time in which each pipe would fill the cistern?????

Posted by Sneha Singh 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Nikhil Chauhan 6 years, 10 months ago

Let time taken by first pipe = x min. So, time taken by second pipe = x+3 min. Now, Cistern fill in 1hr by first pipe= 1/x And cistern fill in 1hr by second pipe= 1/x+3 So, Acc. To que. = 1/x + 1/x+3 = 1/40/13 = x+x+3/x^2+3x = 13/40. (LCM) =2x+3/x^2+3x = 13/40 =13x^2+39x = 80x+120 =13x^2- 41x- 120=0 On solving this equation we get, x=5 and x=-24/13 It is not possible So, Time taken by first pipe=5 min. And time taken by second pipe=5+3 =8 min.

1Thank You

Sneha Singh 6 years, 10 months ago

Can u please solve it fully

1Thank You

Anchal Kaurav 6 years, 10 months ago

smaller 5 larger 8

0Thank You

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