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Ex 10.2 question no.5

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Ex 10.2 question no.5
  • 2 answers

Drashti Vaish 6 years, 10 months ago

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Khushboo Giri 6 years, 10 months ago

Given: a circle c(o,r), <QPB=90° Prove that:QP passes through center O Prove:we know that line joining the center and point of contact on the tangent is perpendicular. Therefore, OP perpendicular to AB. <OPB=90 <QPB=90 <QPB+<OPB=90+90 =180 this two angles are adjacent angles. They are linear pair. Therefore, QP passes through center O.
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