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Given that the zeroes of the …

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Given that the zeroes of the cubic polynomial X^3-6X^2+3X+10 are of the form a,a+b,a+2b for some real numbers a" and b"as then find a and b well as well as the zeroes of the given polynomial

    • Posted by Amrish Chaubey 6 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Veeraraghavan Pandurangan 6 years, 10 months ago

    x^3-6x^2+3x+10 P(2)=0 Therefore (x-2) is a factor x^3-6x^2+3x+10/(x-2) =x^2-4x-5 =(x-5)(x+1) There fore factors are(x-2)(x-5)(x+1) Zeroes of the equation -1,2,5 They are in form. -1,-1+3,-1+2*3 Hence a=1 and b=3

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