Find th ratio of the area …

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Ram Kushwah 6 years, 10 months ago
{tex}\begin{array}{l}\text{Let r is radius thn d=2r}\\\frac{area\;of\;circle}{area\;of\;trangle\;}=\frac{\pi r^2}{\sqrt3/4\times d^2}=\frac{4\pi r^2}{\sqrt3\times(2r)^2}\\=\frac{4\pi r^2}{\sqrt3\times4r^2}=\frac\pi{\sqrt3}\end{array}{/tex}
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