In triangle abc ,ab=5,ac=13 ,find the …

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Ram Kushwah 6 years, 10 months ago
{tex}\style{font-size:12px}{\begin{array}{l}AB=5,AC=13\\\mathrm{So}\;\mathrm{BC}^2=\mathrm{AC}^2-\mathrm{AB}^2\\=169-25=144\\\mathrm{BC}=12\\\mathrm{Now}\;\mathrm{tanA}+\mathrm{cotC}\\=\frac{\mathrm{BC}}{\mathrm{AB}}+\frac{\mathrm{AB}}{\mathrm{BC}}\\=\frac{12}5+\frac5{12}=\frac{144+25}{60}=\frac{169}{60}\end{array}}{/tex}
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