Given that root 2 is irrational …
CBSE, JEE, NEET, CUET
Question Bank, Mock Tests, Exam Papers
NCERT Solutions, Sample Papers, Notes, Videos
Posted by Best Videos By Kratik 6 years, 6 months ago
- 1 answers
Test
Related Questions
Posted by Parinith Gowda Ms 3 months, 3 weeks ago
- 1 answers
Posted by Parinith Gowda Ms 3 months, 3 weeks ago
- 0 answers
Posted by Lakshay Kumar 1 year, 1 month ago
- 0 answers
Posted by Kanika . 1 month, 1 week ago
- 1 answers
Posted by Sahil Sahil 1 year, 5 months ago
- 2 answers
Posted by Hari Anand 6 months, 2 weeks ago
- 0 answers
Posted by Vanshika Bhatnagar 1 year, 5 months ago
- 2 answers
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Sia ? 6 years, 6 months ago
Let 5 + 3{tex}\sqrt{2}{/tex} be a rational number.
{tex}\Rightarrow{/tex} 5 + 3{tex}\sqrt{2}{/tex} = {tex}\frac{p}{q}{/tex}, p, q {tex}\in{/tex} I, q {tex}\ne{/tex} 0
{tex}\Rightarrow{/tex} 3{tex}\sqrt{2}{/tex} = {tex}\frac{p}{q}{/tex} - 5{tex}\Rightarrow \sqrt{2}{/tex} = {tex}\frac{p - 5q}{3q}{/tex}
{tex}\frac{p - 5q}{3q}{/tex} is rational {tex}\Rightarrow{/tex} {tex}\sqrt{2}{/tex} is rational number which is a contradiction.
5 + 3{tex}\sqrt{2}{/tex} is irrational number.
0Thank You