The mean and median of 100 …
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Sia ? 6 years, 6 months ago
It is given that the mean of 100 observations is 50 . The value of the largest observation is 100.
Mean = {tex}\frac { \Sigma f x } { \Sigma f }{/tex}
{tex}\Rightarrow{/tex} 50 = {tex}\frac { \Sigma f x } { 100 }{/tex}
{tex}\Rightarrow \quad \Sigma f x {/tex} = 5000
It was later found that it is 110 not 100.
Correct, {tex}\Sigma f x ^ { \prime }{/tex} = 5000 + 110 - 100 = 5010
Therefore, Correct Mean = {tex}\frac { \Sigma f x' } { \Sigma f }{/tex} {tex}= \frac { 5010 } { 100 } {/tex}= 50.1
It is given that the median of 100 observations is 52.
Median will remain same i.e. = 52
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