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If secA+tanA=p show that secA-tanA=1/p hence …

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If secA+tanA=p show that secA-tanA=1/p hence find the values of sinA and cosA

Posted by Madhura Kaware 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Chaithanya Sreedharan 6 years, 10 months ago

Sec A + Tan A =p -equation 1 We know that Sec^2 A - Tan^2 A = 1 (Sec A -Tan A)(Sec A+ Tan A)=1[a^2 -b^2 =(a+b)(a-b)] From equation 1 (Sec A - Tan A)(p) = 1 Sec A - Tan A=1÷p -equation 2 Adding equations 1 and 2 Sec A - Tan A +Sec A+ Tan A=(1+p^2)/p 2 Sec A =(1+p^2)/p Sec A=(1+p^2)/2p Now you can easily find the value of sin and cos

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Immortal 2K17009 6 years, 10 months ago

Answer, SecA+tanA=p --------------eq1 Now, Sec^2A-tan^2A=1. (a^2-b^2) (SecA+tanA)(secA-tanA)=1 (a+b)(a-b) p(secA-tanA)=1. (using eq1) secA-tanA=1/p PROVED

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Honey ??? 6 years, 10 months ago

Shift tan to rhs and sq. on both sides and find value of tan in trms of p and put the values in a triangle and then find the t ratios.

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