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Determine the AP whose third term …

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Determine the AP whose third term is 16 and 17th term exceeds the 5th term by 12
  • 4 answers

Ram Kushwah 6 years, 10 months ago

Here A3= a+2d=16.....(1)

A17-A5=(a+16d)-(a+4d)=12

or 12d=12

Hence d=1

from (1)

a+2=16, a=14

Thus the series is 14,15,16,17,18.......

 

Drashti Vaish 6 years, 10 months ago

Hope so you can understand... if you are having any doubt regarding this question so please ask to me thankuuu

Drashti Vaish 6 years, 10 months ago

A3=16 a+2d=16 a=16 - 2d We have got the value of a Again A.T.Q A17 - A5= 12 a+16d - (a+4d) =12 On putting the value of a=16 -2d 16 - 2d + 16d - 16 - 2d - 4d = 12 16 will be cancel... So, -2d +16d -2d - 4d= 12 -4d +12d = 12 8d=12 d= 12/8 d=3/2 We have got the value of d=3/2 Now putting the value of d into the equation of a a =16 -2 ×3/2 a= 16 -3 a = 13.. So we have got the value of both a and d...

Sejal ??? 6 years, 10 months ago

4,10,16,22,28
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