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Gaurav Seth 6 years, 10 months ago
Energy band gap of the given photodiode, <i>E</i><i>g</i> = 2.8 eV
Wavelength, λ = 6000 nm = 6000 × 10−9 m
The energy of a signal is given by the relation:
<i>E</i> =
Where,
<i>h</i> = Planck’s constant
= 6.626 × 10−34 Js
c = Speed of light
= 3 × 108 m/s
<i>E</i>
= 3.313 × 10−20 J
But 1.6 × 10−19 J = 1 eV
∴<i>E</i> = 3.313 × 10−20 J
The energy of a signal of wavelength 6000 nm is 0.207 eV, which is less than 2.8 eV − the energy band gap of a photodiode. Hence, the photodiode cannot detect the signal.
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