Three consecutive vertices of a parallelogram …

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Gaurav Seth 6 years, 10 months ago
Let A(-2, -l), B(1, 0). C(4, 3) and D(x, y) be the vertices of a parallelogram ABCD taken in order. Since, the diagonals of a parallelogram bisect each other. Therefore coordinates of the mid-point of AC = Coordinates of the mid-point of BD.
(-2+4/2, -1+3/2) = (1+x/2, 0+y/2)
(1,1) = (1+x/2 , y/2)
x+1 = 2, y=2
Therefore (1,2) is the fourth vertex.
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