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State and prove the Pythagoras theorm

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State and prove the Pythagoras theorm
  • 3 answers

Purvanshi Yadav 6 years, 10 months ago

Phythagoras th. - In a right ∆ the square of hypo. is equal to sum of squares of other 2 sides. Construct a ∆ABC in which D is perpendicular to AC. ∆ADB~∆ABC (By AA similarity) ----(1) Similarly ∆BDC~ABC∆ ------(2) Now; AD/AB=AB/AC (from 1) So by cross multiplying AB2=AD×AC-----(3) Next; DC/BC=BC/AC (from 2) Again by cross multiplying BC2= AC×DC-----(4) Now from adding (3) and (4) we have; AB2+BC2=(AD×AC)+(AC×DC) AB2+BC2= AC(AD×DC) AB2+BC2=AC×AC AB2+ BC2= AC2 {Hence Proved}

Naitik Garg 6 years, 10 months ago

You can get this theorm in ncert book just open the book and see

Priyanshi Mishra 6 years, 10 months ago

See from ncert
https://examin8.com Test

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