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Find the value of p, for which one root of quadratic equation PX2-14X+8=0is 6 times the other

Posted by Pushpender Chauhan 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

?☠Debraj Bairagi☠? 6 years, 10 months ago

P=+-3

0Thank You

Gaurav Seth 6 years, 10 months ago

Given

px²-14x+8=0
let a and b be the roots of the equation
b=6a
sum of roots = -b/a
product of roots = c/a
here a=p , b=-14 , c=8
a+b=14/p
ab=8/p

a+6a=14/p
7a=14/p
a=2/p

a*6a=8/p
6a²=8/p
3a²=4/p

3*(2/p)²=4/p

3*4/p²=4/p

p=3

1Thank You

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