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(Sec 60+tan 60)(1-sin 60)

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(Sec 60+tan 60)(1-sin 60)

Posted by Uzzwal Upadhyay 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Yogita Ingle 6 years, 10 months ago

than 60 = √3
sec 60 = 2
sin 60 = √3/2
( sec 60 + tan 60)(1 - sin60)
= (2+ √3)( 1 - √3/2)
= (2 + √3) [(2 -√3)/2]
= ](2)² - (√3)²]/ 2
= 4 - 3 /2
= 1/2

Puja Sahoo? 6 years, 10 months ago

1/2

Honey ??? 6 years, 10 months ago

1/2

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