No products in the cart.

Simplify and factorise (a+b+c)^2-(a-b-c)^2+4b^2-4c^2

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

Simplify and factorise (a+b+c)^2-(a-b-c)^2+4b^2-4c^2
  • 1 answers

Yogita Ingle 6 years, 10 months ago

(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Consider, (a+b+c)2 – (a – b – c)2+ 4b2– 4c2
= a2 + b2 + c2 + 2ab + 2bc + 2ca – (a2 + b2 + c2 – 2ab + 2bc – 2ca)+ 4b2– 4c2
= a2 + b2 + c2 + 2ab + 2bc + 2ca – a2 – b2 – c2 + 2ab – 2bc +2ca + 4b2– 4c2
= 4ab + 4ca + 4b2– 4c2
= 4(ab + ca + b2– c2)
= 4[a(b + c) +(b2– c2)]
= 4[a(b + c) + (b + c)(b – c)]
= 4(b + c)(a + b – c)

https://examin8.com Test

Related Questions

X³-12x²+39x-28
  • 0 answers
What is 38747484±393884747
  • 0 answers
2x²+[1×(8x²)^-1]+1
  • 0 answers
3√2×4√2×12√32
  • 0 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App