Simplify and factorise (a+b+c)^2-(a-b-c)^2+4b^2-4c^2

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Posted by Palak Gaba 6 years, 10 months ago
- 1 answers
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Yogita Ingle 6 years, 10 months ago
(a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
Consider, (a+b+c)2 – (a – b – c)2+ 4b2– 4c2
= a2 + b2 + c2 + 2ab + 2bc + 2ca – (a2 + b2 + c2 – 2ab + 2bc – 2ca)+ 4b2– 4c2
= a2 + b2 + c2 + 2ab + 2bc + 2ca – a2 – b2 – c2 + 2ab – 2bc +2ca + 4b2– 4c2
= 4ab + 4ca + 4b2– 4c2
= 4(ab + ca + b2– c2)
= 4[a(b + c) +(b2– c2)]
= 4[a(b + c) + (b + c)(b – c)]
= 4(b + c)(a + b – c)
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