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If cos(a+b)=0, show that sin (a-b)=cos 2b

Posted by Priyanshu Golu 6 years, 10 months ago

CBSE > Class 10 > Mathematics

2 answers

Sonu Kumar 6 years, 10 months ago

Cos(a+b)=0 Cosa+cosb=0 Cosa= -cosb We take rhs Sin(a-b) Sina-sinb Cos(90-a) -cos(90-b) Cos90-cosa -cos90+cosb -cosa+cosb -(-cosb) + cosb Cosb+ cosb Cos(b+b) Cos2b prooved

3Thank You

Avinash Saigal 6 years, 10 months ago

Cos(a+b)= 0 (a+b)= 90 a=(90-b) Sin(a-b)= sin ( 90-2b) Since, sin (A-B)= sinA* cosB - cosA* sinB Sin(90-2b)= sin90*cos2b - cos90 -sin2b 1*cos2b -0*sin2b Hence answer is cos2b...... Thank you??

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CBSE > Class 10 > Mathematics