find the ratio of the orbital …
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Posted by Kunal Kishore 6 years, 10 months ago
- 4 answers
Gaurav Seth 6 years, 10 months ago
Q. What is the value of Sin(31π/3)
= sin(31π/3)
= sin(10π+π/3)
= sin(π/3)
= √3/2 ( in quadrant 1 )
OR
Sin ( 31 x 180 / 3)
= sin ( 31 x 60)
= sin(1860)
= sin(5x360 - 60)
=sin60
=root3/2
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Prakhar J 6 years, 10 months ago
0Thank You