Derivation of cp-cv=R
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Posted by Alok Kumar 6 years, 10 months ago
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Gaurav Seth 6 years, 10 months ago
Consider one mole of an ideal gas enclosed in a cylinder fitted with the movable frictionless piston.
Let the gas be heated at constant volume.
CpdT = Cv x dT + RdT
On supplying dQ amount of heat, let the temperature of the gas increase by dT.
By first law of thermodynamics,
dQ = dU + dW = dU + PdV
At a constant pressure,
P.dV = R.dT
where Cp, Cv and R are in same units.
Hence, proved.
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