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If x=a sec A+ b tan …

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If x=a sec A+ b tan A and y=a tan A+ b sec A, prove that x^2-y^2=a^2-b^2
  • 1 answers

Purvanshi Yadav 6 years, 10 months ago

X= a secA+b tanA Y= a tanA+b secA On squaring we get the following; X2+Y2= a2 sec2A+b2 tan2A - (a2 tan2A+b2 sec2A) X2+Y2=a2 sec2A+b2 tan2A - a2- tan2A-b2-sec2A X2+Y2= a2-b2 hence proved.
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