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Prove the no is irrational no …

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Prove the no is irrational no √2
  • 2 answers

Paras ? ? Shah ? ? 6 years, 10 months ago

Let us take √2 is rational We can take x and y √2 = x/y Suppose x and s have a common factor other than 1. Then you have to divide by the common factor √2 = a/ b, where a and b are coprime. So b √2 = a On sq. Both side 2b ka 2 = a ka 2 2 divide a ka 2. So we take another integer c. a = 2c We get 2b ka 2 = 4c ka 2 b ka 2 = 2c ka 2 That means 2 divide b ka 2 and so 2 divides b. Therefore a and b have at least 2 as a common factor. This contradiction has arisen because of our incorrect assumption that √ 2 is rational. So, we conclude that √2 is irrational.
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