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An iron pillar has lower part …

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An iron pillar has lower part in the form of right circular cylinder and the upper part In the form of right circular cone .the radius of the base of each of the cone and cylinder is 8 cm. The cylindrical part is 240 cm high and the conical part is 36 cm high. find the weight of the pillar , if 1 cm cube of iron weights 7.5g
  • 1 answers

Gaurav Seth 6 years, 10 months ago

Let r1 and r2 cm be the radii of the base of the cylinder and cone respectively. Then, r1 = r2 = 8 cm Let h1 and h2 cm be the heights of the cylinder and the cone respectively. Then,

h1 = 240 cm and h2 = 36 cm

Now, Volume of the cylinder = r12h1 cm3 = ( x 8 x 8 x 240) cm3 = ( x 64 x 240) cm3
Volume of the cone = 
Total volume of the iron = Volume of cylinder + Volume of the cone


Hence, total weight of the pillar = Volume x Weight per cm3
= (22 x 64 x 36 x 7.5) = 380.16 kg
 

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