An iron pillar has lower part …

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Gaurav Seth 6 years, 10 months ago
Let r1 and r2 cm be the radii of the base of the cylinder and cone respectively. Then, r1 = r2 = 8 cm Let h1 and h2 cm be the heights of the cylinder and the cone respectively. Then,
h1 = 240 cm and h2 = 36 cm

r12h1 cm3 = (
x 8 x 8 x 240) cm3 = (
x 64 x 240) cm3

Now, Volume of the cylinder =
Volume of the cone =
Total volume of the iron = Volume of cylinder + Volume of the cone
Hence, total weight of the pillar = Volume x Weight per cm3
= (22 x 64 x 36 x 7.5) = 380.16 kg
2Thank You