No products in the cart.

A circle touches the side BC …

CBSE, JEE, NEET, CUET

CBSE, JEE, NEET, CUET

Question Bank, Mock Tests, Exam Papers

NCERT Solutions, Sample Papers, Notes, Videos

A circle touches the side BC and triangle abc at P and touches AB and AC produced at Q and R respectively. prove that AQ equal to 1/2 (perimeter of triangle ABC)
  • 1 answers

Gaurav Seth 6 years, 10 months ago

Sol:

Given:  A circle touching the side BC of ΔABC at P and AB, AC produced at Q and R respectively.

RTP: AP = 1/2 (Perimeter of ΔABC)

Proof: Lengths of tangents drawn from an external point to a circle are equal.
          ⇒ AQ = AR, BQ = BP, CP = CR.
          Perimeter of ΔABC = AB + BC + CA
                                      = AB + (BP + PC) + (AR – CR)
                                      = (AB + BQ) + (PC) + (AQ – PC) [AQ = AR, BQ = BP, CP = CR]
                                      = AQ + AQ
                                      = 2AQ

           ⇒ AQ = 1/2 (Perimeter of ΔABC)
 
           ∴ AQ is the half of the perimeter of ΔABC.

https://examin8.com Test

Related Questions

(A + B )²
  • 1 answers
Prove that root 8 is an irration number
  • 2 answers
sin60° cos 30°+ cos60° sin 30°
  • 2 answers
Venu Gopal has twice
  • 0 answers
Find the nature of quadratic equation x^2 +x -5 =0
  • 0 answers
X-y=5
  • 1 answers

myCBSEguide App

myCBSEguide

Trusted by 1 Crore+ Students

Test Generator

Test Generator

Create papers online. It's FREE.

CUET Mock Tests

CUET Mock Tests

75,000+ questions to practice only on myCBSEguide app

Download myCBSEguide App