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If tanA+sinA=m and tanA - sinA …

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If tanA+sinA=m and tanA - sinA =n, show that m^2−n^2= 4√mn

Posted by Ankul Prajapati 6 years, 10 months ago

CBSE > Class 10 > Mathematics

1 answers

Ayushi Jain 6 years, 10 months ago

Lhs (tan A+sin A )(tan A-sin A) _(tanA+sin A)(tan A-sin A) =(2tan A)(2sin A) =4tan A sin A Rhs 4√(tanA+sin A)(tanA-sinA) 4√tan Square A-sin square A 4√tan square A_sin square A 4√sin square A/cos square A_sin square A 4√sin square A (1/cos square A-1) 4√sin square A (sec square A-1) 4√sin square A tan square A 4 sin A tan A Hence proved

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CBSE > Class 10 > Mathematics