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If asintheda +b costheda =c then …

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If asintheda +b costheda =c then prove that a costheda -bsintheda =+- √a square + b square - c square ??
  • 1 answers

Raj Kumar 6 years, 10 months ago

(asintheda + bcostheda) ka whole square + (acostheda - bsintheda) ka whole square = a square + b square. Now, (asintheda +bcostheda)^2 (acostheda - bsintheda) ^2 = a^2 + b^2 => c^2 +(acostheda - bsintheda)^2= a^2 + b^2 => acostheda - bsintheda = +_ root under a^2 +b^2 - c^2 ...........proved
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