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Two water taps together can fill a tank in 9 3/8 hours. The tap of larger diameter takes 10 hours less than the smaller one to fill the tank separately. Find the time in which each tap can separately fill the tank.

Posted by Shreenidhi Karkun 6 years, 10 months ago

CBSE > Class 10 > Mathematics

3 answers

Geetanand Yadav/ Rao Sahab??????✌??? 6 years, 10 months ago

For small tap 18 hours and for big tap 12hours

Rita Gokani 6 years, 10 months ago

Let the time taken by smaller tap be xhrs And larger =x-10hrs ATQ 1/X +1/X-10=8/75 SOLVE...

S N Mahato 6 years, 10 months ago

Let time taken by the largest tap to fill the tank completely be x hours Then volume it can fill in 1 hour is 1/X Then volume it can fill in 75/8 hours is75/8x Then time taken by smaller tab to fill the tank completely is X + 10 hours Volume it can fill in 1 hour is 1/X + 10 Then volume it fill in 75/8 hours is 75 / 8 ( X + 10) Tank filled by the largest tab + tank filled by smaller tab = 1 A/Q..... 75 / 8X + 75 / 8 (x + 10 )= 1 By calculating this you will get the answer .thank you

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