If one zero of polynomial ( …
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Sia ? 5 years, 10 months ago
Let α and 1α be the zeros of (a2 + 9)x2 + 13x + 6a.
Then, we have
α×1α=6aa2+9
⇒ 1 = 6aa2+9
⇒ a2 + 9 = 6a
⇒ a2 - 6a + 9 = 0
⇒ a2 - 3a - 3a + 9 = 0
⇒ a(a - 3) - 3(a - 3) = 0
⇒ (a - 3) (a - 3) = 0
⇒ (a - 3)2 = 0
⇒ a - 3 = 0
⇒ a = 3
So, the value of a in given polynomial is 3.
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