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Sia ? 6 years, 4 months ago
Let n =3k
then n + 2 = 3k + 2
and n + 4 = 3k + 4
Case 1: When n=3k ,n is divisible by 3 ............(1)
n + 2 = 3k + 2
or, n + 2 is not divisible by 3
n + 4 = 3k + 4
= 3(k + 1) + 1
or, n + 4 is not divisible by 3
Case 2:When n=3k+1, n is not divisible by 3
n + 2 = (3k + 1) + 2
=3k + 3 = 3(k + 1)
{tex} \Rightarrow{/tex} n+ 2 is clearly divisible by 3..........................(2)
n + 4 = (3k + 1) + 4
= 3k + 5
= 3(k + 1) + 2
{tex}\Rightarrow{/tex} n + 4 is not divisible by 3
Case 3:When n=3k+2,n is not divisible by 3
n + 2 = (3k + 2) + 2
= 3k + 4
(n + 2) is not divisible by 3
x + 4 = 3k + 6 = 3(k + 2)
{tex}\Rightarrow{/tex} n + 4 is divisible by 3........................(3)
Hence, from (1),(2) and (3) it is clear that exactly one of the numbers n, n + 2, n + 4, is divisible by 3.
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