The volume of a hemisphere is …
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Sia ? 6 years, 4 months ago
As, volume of hemisphere = 2425{tex}\frac { 1 } { 2 } c m ^ { 3 }{/tex}
{tex}\Rightarrow \frac { 2 } { 3 } \pi r ^ { 3 } = 2425 \frac { 1 } { 2 }{/tex}
{tex}\Rightarrow \frac { 2 } { 3 } \times \frac { 22 } { 7 } r ^ { 3 } = \frac { 4851 } { 2 }{/tex}
{tex}\Rightarrow r ^ { 3 } = \frac { 4851 \times 3 \times 7 } { 2 \times 2 \times 22 }{/tex}
{tex}\Rightarrow r ^ { 3 } = \frac { 441 \times 3 \times 7 } { 2 \times 2 \times 2 }{/tex}
{tex}\Rightarrow r ^ { 3 } = \frac { 21 ^ { 3 } } { 2 ^ { 3 } }{/tex}
{tex}\Rightarrow r = \frac { 21 } { 2 } c m{/tex}
So, the curved surface area of the hemisphere ={tex}2 \pi r ^ { 2 }{/tex}
{tex}= 2 \times \frac { 22 } { 7 } \times \frac { 21 } { 2 } \times \frac { 21 } { 2 } = 693 \mathrm { cm } ^ { 2 }{/tex}
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