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(CosecA-sinA) (secA-cosA)=1/tanA+cotA

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(CosecA-sinA) (secA-cosA)=1/tanA+cotA
  • 1 answers

Yash Kanchan 6 years, 10 months ago

Cosec-sin×sec-cos =lhs cosec-1/cosec×sec-l/sec=cosec2 -1/cosec ×sec2-1/sec=cot2/cosec×tan2/sec=cos2/sin2/1/sin×sin/cos2/1/cos=sin×cos RHS=1/sin/cos+cos/sin=sin2+cos2/sin×cos=sin×cos LHS=RHS 2is square
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