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2cosQ+2√2=3secQ find Q solve step by …

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2cosQ+2√2=3secQ find Q solve step by step and give ans
  • 2 answers

Varnika Prasad 6 years, 10 months ago

( r MEANS ROOTS..... SO DON'T GET CONFUSED ) 2cosQ +2r2 = 3secQ 2cosQ + 2r2 = 3/ cosQ 2cos^2Q + 2r2cosQ = 3 (Multiplying the eq. by r2) 2r2cos^2Q + 4cosQ -3r2 = 0 2r2cos^2Q - 2cosQ + 6cosQ - 3r2 = 0 ( by factorization we get ) cosQ = 1/r2 and cosQ = -3r2/2 (u can find it out and get same result) Since the value of cosQ can't be negative Therefore the actual value of cosQ is 1/r2 And hence Q is 45°

Abhishek Jain 6 years, 10 months ago

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