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9sec2A-9tan2A

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9sec2A-9tan2A

    • Posted by Mjsk Giridih 6 years, 10 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Sneha Singh 6 years, 10 months ago

    = 9 (sec²a - tan²a) = 9(1/cos²a - sin²a/cos²a) = 9 ( 1- sin²a / cos²a) = 9 ( cos²a/ cos²a) = 9 ×1 = 9

    1Thank You

    Honey ??? 6 years, 10 months ago

    9

    1Thank You

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