Draw an isosceles triangle ABC in …

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Sia ? 6 years, 4 months ago
We have to draw
ΔPQR ~ ΔABC
PQ = 8 cm
∴ {tex}\frac { P Q } { A B } = \frac { 8 } { 6 } = \frac { 4 } { 3 }{/tex} (∵ AB = 6 cm)
So, PQ = QR = 8 cm
So, we have to draw ΔPQR ~ ΔABC with scale factor {tex}\frac { 4 } { 3 }{/tex} > 1 resulting ΔPQR will be larger than ΔABC.
Steps of Construction:
Therefore, ΔPQR ~ ΔABC with PQ = PR = 8 cm. It’s scale factor is {tex}\frac { 4 } { 3 }{/tex}.
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