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500 persons have to dip in a rectangular tank which is 80m long and 50m broad. what is the rise in the level of water in the tank, if the average displacement of water by a person is 0.04m cube

Posted by Siva Srinivasan 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Suppose level of water rises by h metres in the pond. Then, clearly, water risen in the pond forms a cuboidal of dimensions {tex}80 \mathrm { m } \times 80 \mathrm { m } \times \mathrm { hm }.{/tex}
{tex}\therefore \quad 80 \times 50 \times h{/tex}= Volume of water displaced by 500 persons
{tex}\Rightarrow \quad 80 \times 50 \times h = 500 \times 0.04{/tex}
{tex}\Rightarrow{/tex} 4000h = 20
{tex}\Rightarrow \quad h = \frac { 1 } { 200 } \mathrm { m } = 0.5 \mathrm { cm }{/tex}

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